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【332777】2.2 第2课时 利用内错角、同旁内角判定两条直线平行2

时间:2025-02-07 08:56:58 作者: 字数:9800字
简介:

1.如图,EBC的延长线上,下列条件中不能判定AB∥CD的是(  )
Shape1

A. ∠3=∠4                        B. ∠1=∠2                        C. ∠B=∠DCE                        D. ∠D+∠DAB=180°

2.如图所示,点EAC的延长线上,下列条件中能判断AB∥CD的是(   ) Shape2

A. ∠3=∠4                       Shape3 B. ∠1=∠2                       Shape4 C. ∠D=∠DCE                       Shape5 D. ∠D+∠ACD=180°

3.如图,下列能判定AB∥CD的条件有(  )个.
1)∠B+∠BCD=180°;(2)∠1=∠2;(3)∠3=∠4;(4)∠B=∠5
Shape6

A. 1                                           Shape7 B. 2                                           Shape8 C. 3                                           Shape9 D. 4

4.如图,给出下列条件:其中,能判断AB∥CD的是 (    )
 ①∠1=∠2          ②∠3=∠4      ③∠B=∠DCE      ④∠B=∠D
Shape10

A. ①或④                                Shape11 B. ②或③                                Shape12 C. ①或③                                Shape13 D. ②或④.

5.如图,下列说法错误的是(  )
Shape14

A. ∠A与∠EDC是同位角                                           B. ∠A与∠ABF是内错角
C. ∠A与∠ADC是同旁内角                                       D. ∠A与∠C是同旁内角

6.如图,下列条件中能判定直线l1∥l2的是(   )
Shape15

A. ∠1=∠2                           Shape16 B. ∠1=∠5                           Shape17 C. ∠1+∠3=180°                           Shape18 D. ∠3=∠5

7.如图所示,下列各组角的位置,判断错误的是(  )
Shape19

A. ∠C和∠CFG是同旁内角                                       Shape20 B. ∠CGF和∠AFG是内错角
C. ∠BGF和∠A是同旁内角                                       Shape21 D. ∠BGF和∠AFD是同位角

8.如图,点EAC的延长线上,下列条件中能判断AB∥CD的是(    )
Shape22

A. ∠3=∠4                       Shape23 B. ∠D=∠DCE                       Shape24 C. ∠1=∠2                       Shape25 D. ∠D+∠ACD=180°

9.如图,下列能判定AB∥CD的条件的个数(   ) (1 )∠B=∠BCD;(2)∠1=∠2;(3)∠3=∠4;(4)∠B=∠5
Shape26

A. 1                                           Shape27 B. 2                                           Shape28 C. 3                                           Shape29 D. 4

10.如下图,在下列条件中,能判定AB//CD的是(     )

Shape30

A. ∠1=∠3                               B. ∠2=∠3                               C. ∠1=∠4                               D. ∠3=∠4

二、填空题(共6题;共10分)

11、如图,ACBC分别平分∠DAB、∠ABE,且∠1与∠2互余, 则______∥_______,理由是_________________________________________

Shape31

12.如图一个弯形管道ABCD的拐角∠ABC=120°,∠BCD=60°,这时说管道AB∥CD,是根据________ 
Shape32

13.如图,要使AD∥BC,需添加一个条件,这个条件可以是________ .(只需写出一种情况)
Shape33

14.如图所示,同位角的个数是________,内错角的个数是________,同旁内角的个数是________
Shape34

15.根据题意可知,下列判断中所依据的命题或定理是________
如图,若∠1=∠4,则AB∥CD;若∠2=∠3,则AD∥BC

Shape35

16.如图,图中内错角有________对,同旁内角有________对,同位角有________对.
Shape36

三、解答题(共3题;共15分)

17.如图,∠B的内错角,同旁内角各有哪些?请分别写出来.
Shape37

18.如图,∠1和∠2是哪两条直线被哪一条直线所截形成的?它们是什么角?∠1和∠3是哪两条直线被哪一条直线所截形成的?它们是什么角?
Shape38

19.如图,已知直线ABCD被直线EF所截,且∠AGE=46°,∠EHD=134°,请判断ABCD平行吗?说明理由.

Shape39



20.如图,∠ABC=∠ADCBFDE是∠ABC、∠ ADC的角平分线,∠1

=∠2,求征DC∥AB。(7

Shape40



21.如图,已知∠1与∠3互余,∠2与∠3的余角互补,问直线 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/866/" title="内错角" class="c1" target="_blank">内错角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> 平行吗?为什么?(8分)

Shape41

答案解析部分(差T15答案

1.A 2.B 3.C 4.C 5.D 6.C 7.C 8.C 9.B 10.C

11.GDHE;同旁内角互补,两直线平行

12.同旁内角互补,两直线平行

13.∠1=∠4

14.241616

15.内错角相等,两直线平行

16.548

17.解:∠B的内错角有∠DAB
∠B的同旁内角有∠C,∠BAC,∠BAE

18.解:∠1和∠2是直线EFDC被直线AB所截形成的同位角,∠1和∠3是直线ABCD被直线EF所截形成的同位角.

19.解:AB∥CD. 理由:∵∠AGE=46°
∴∠BGF=∠AGE=46°
∵∠EHD=134°
∴∠BGF+∠EHD=46°+134°=180°
∴AB∥CD

20.∵BFDE分别是∠ABC、∠ADC的角平分线

∴∠2= <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/866/" title="内错角" class="c1" target="_blank">内错角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> ∠ABC,∠3= <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/866/" title="内错角" class="c1" target="_blank">内错角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> ∠ADC

∵∠ABC=∠ADC

∴∠2=∠3

∵∠1=∠2

∴∠1=∠3

DC∥AB