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【332774】2.2 第1课时 利用同位角判定两条直线平行1

时间:2025-02-07 08:56:49 作者: 字数:2743字
简介:


1.如图,直线CDEF被第三条直线AB所截,则∠1与∠2是(  )
 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>

A. 同位角                               B. 内错角                                C. 同旁内角                               D. 对顶角

2.如图,图形中不是同位角的是(  )
 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>

A. ∠3与∠6                           B. ∠4与∠7                         C. ∠1与∠5                           D. ∠2与∠5

3.如图,木工用图中的角尺画平行线的依据是________ 
 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>

4.如图把三角板的直角顶点放在直线b上,若∠1=40°,则当∠2=________ 度时,a∥b
 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>

5.已知:如图,∠EAD=∠DCF,要得到AB∥CD,则需要的条件________.(填一个你认为正确的条件即可)

 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>

6 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> .如图,已知直线 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> 被直线 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> 所截,∠1120°,当∠2等于多少度时, <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a> <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>






7.如图,∠1=∠2=∠3,找出图中哪些线平行,并说明理由.

 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>  <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>


[来源:++Z+X+X+K]





8.如图,∠1=∠2=55°直线ABCD平行吗?说明你的理由.

[来源:Zxxk.Com]

 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>




[来源:Zxxk.Com]


[来源:..Z.X.X.K]

9.如图,∠B=∠CBAD三点在同一直线上,∠DAC=∠B+∠CAE是∠DAC的平分线,求征:AE∥BC.

 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>

9.∵∠DAC=∠B+∠C,∠B=∠C

∴∠DAC=2∠B,∠1=∠2

∴∠1=∠B

AE∥BC

10.如图,已知直线ABCD被直线EF所截,如果∠BMN=∠D NF,∠1=∠2,那么MQ∥NP,试写出推理.

 <a href="/tags/16/" title="课时" class="c1" target="_blank">课时</a> <a href="/tags/58/" title="平行" class="c1" target="_blank">平行</a> <a href="/tags/78/" title="直线" class="c1" target="_blank">直线</a> <a href="/tags/450/" title="利用" class="c1" target="_blank">利用</a> <a href="/tags/867/" title="同位角" class="c1" target="_blank">同位角</a> <a href="/tags/868/" title="判定" class="c1" target="_blank">判定</a>

10.∵∠BMN=∠DNF,∠1=∠2

∴∠BMN+∠1=∠DNF+∠2

即∠QMN=∠PNFMQ∥NP