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【332019】七年级数学参考答案

时间:2025-02-09 11:45:45 作者: 字数:3790字
简介:

安庆市2018—2019学年度第学期初中二十三校联考

年级数学试卷参考答案及评分标准

一、选择题:

题号

1

2

3

4

5

6

7

8

9

10

答案

A

D

C

B

B

D

D

C

D

A

二、填空题:11 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> 122 13  <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> 14 8

 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a>

15

解:原式=  <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> …………每对一个得1

211

0 …………10

Shape1

 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a>

 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a>




16.



解:由 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a>

 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> …………每对一个得3

画数轴 (略) …………2

所以不等式组的解集是 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> . …………10

17.  <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a>

解原式= <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> …………5

 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> …………7

 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> …………8

1 …………10

18. <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> 其中 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> , <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> .

解:原式= <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> …………每对一个公式得2

 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> …………5

 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> …………7

上式= <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> …………8

=-2 …………10


 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a>


19.x=12…………4

、解:由 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> 得,

 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a>

所以 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> 转化为

 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> …………8

解得 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> …………10

所以不等式负整数解为-1 …………12



20.解设:购买A设备x台, …………1

Shape2

 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a>

12x+1610x <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> 142


由题意得: …………7

解得 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> …………9

所以x可取34. …………10分,

从而购买AB设备方案如下:


方案

1

2

A台数

3

4

B台数

7

6



…………12分。


  1. 解:租用Ax辆 , …………1

由题意得:400x+2805x <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> 1900 …………3

解得 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> …………4

所以x可取01234. …………5

所以租用车方案为:

方案

1

2

3

4

5

A

0

1

2

3

4

B

5

4

3

2

1

…………6

解:租用Ax辆 ,

由题意得:48x+305x <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> …………9

解得 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> 所以x至少为3,由x可取34. …………10

x3时,费用为1760元,当x4时,费用为1880元,所以A车租3辆,B车租2辆最省钱。 …………12


22.

172135352171…………4分,可酌情给分


 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a>

 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a>

 <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> ,显然满足“杨辉三角”第四行系数。………8

、运用“杨辉三角”展开,解不等式得: <a href="/tags/46/" title="答案" class="c1" target="_blank">答案</a> <a href="/tags/55/" title="数学" class="c1" target="_blank">数学</a> ,

过程此处略,要求学生有具体展开过程 ………14

易度题:1234671112151617182021总分值98分,

中度题:58913141922,总分值38

难度题:1022 ,总分值14